Lv 7. 4 NH3 + 5 O2 → 4 NO + 6 H2O (80.0 g O2) / (31.99886 g O2/mol) = 2.5001 mol O2 (70.0 g NH3) / (17.03056 g NH3/mol) = 4.1103 mol NH3. C5H12 + 8O2 → 5CO2 + 6H2O Calculate the energy change for the reaction: 1 See answer (bond energy) yousuflikeskars is waiting for your help. Then I balanced H on product side, and added a coefficient of 6 to make it 12. What is the oxidizing agent when iron rusts? Similar Questions. A negative sign is used with rates of change of reactants and a positive sign with those of products, ensuring that the reaction rate is always a positive quantity. 92.8 g of CO2 . Question 1 Using the equation, C5H12 + 8O2 5CO2 + 6H2O, if 2 moles of pentane (C5H12) were supplied, and an unlimited amount of oxygen were available, how many moles of water would be produced? Relevance. 26 g. If 58 moles of NH3 are combined with 32 moles of sulfuric acid, what is the limiting reactant and how much of the excess reactant is left over? ____ —> Li2O. C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield. Relevance. Law of conservation of mass is discussed where the total mass of the reactant and the total mass of the product is conserved. Question #fee47 Question #c5c15 Question #19eb9 Question #e2ea2 Question #bc751 Question #e2ea6 Question … 9 moles of reactants chemically change into 11 moles of products b. 1:6 6:8 8:1 10:8 . Identify which reactant is reduced and which is oxidized in each of the following reactions.? How many ml of 6.00 m naoh is needed to prepare 250 ml of 0.600 m naoh? Answer Save. 85% (69 ratings) Problem Details . To … So all that was left was to add 8 in front of O2 on reactant side. So there has to be 5 carbons and then 6 hydrogens (12/2 =6) . C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield. To produce 4 moles of water, 4/6 moles of pentane must react. 2 Answers. Answers: 1 Get Other questions on the subject: Chemistry. Chemistry what is the 1. chemical equation 2. complete ionic equation 3. net ionic equation include phase of … Your Response. This made Hydrogen balance also, and it gave oxygen a 16 on product side. C5H12(l) + 8O2(g) ----> 5CO2(g) + 6H2O(g) Calculate the standard reaction enthalpy for this reaction using standard enthalpies of formation. C5H12 + 8O2 → 6H2O + 5CO2. Favorite Answer. C5H12 + 8O2 -----> 5CO2 + 6H20 Thus the equation is given below: Li + O2 —> Li2O. 9 years ago. On the product side you have CO2 and H2O. I have the answers but need help on how to work the problems out please. 1 Answer Candy Mar 20, 2018 #21.80# moles. Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O. Here's the balanced equation: C5H12 + 8O2 - 5CO2 + 6H20 Hence the molar ratio of oxygen to pentane is 8:1 . Roger the Mole. 1. Stoichiometry is the calculation between the relationship of reactant and product in a balanced chemical reaction. Choices B and D are incorrect because they both have two reactants. a) C5H12(l) + 8O2(g) -> 5CO2(g) + 6H2O(g) b) 2Al(s) + 3Cu2+(aq) -> 2Al+3(aq) + 3Cu(s) c) 2Cr+3(aq) + 3Zn(s) -> 2Cr(s) + 3Zn+2(aq) d) 2Au+3(aq) + 3Cd(s) -> 2Au(s) + 3Cd+2(aq) 2. Company #2: Hello Equation: C5H12 + 8O2 = 5CO2 + 6H2O Reaction: Combustion Company #1 Neils Bohr 3Na2CO3 856lbs 388,275.07g 1320.62 Company #1 Neils Bohr 2AlPO4 165lbs 74,842.74 306.86 Company #2 Hello C5H12 663lbs 300,731.74 4,166.99 Company #2 Hello 8O2 728lbs 330,215.25 1,289.90 Limiting reactant: “Neils Bohr” 2AlPO4 Excess amount: 860.1 Limiting reactant: … ,v wkh surfhvv ri exuqlqj wkh frpelqdwlrq ri dq rujdqlf vxevwdqfh zlwk r[\jhq wr surgxfh d iodph :khq dq rujdqlf frpsrxqg exuqv lq r[\jhq wkh fduerq uhdfwv zlwk r[\jhq wr irup &2 Equation for the combustion of pentane needed= 4/6mol … C5H12 + 8O2 -- -- - > +... + O2 — > 5CO2 + 6H20 Hence the molar ratio of are... From iron ore is shown below 8:53 pm Has upvoted: 872 times to work problems. Which is oxidized in each of the product is conserved -- > 5CO2 + 6H2O what is the maximum of... The problems out please is the mole ratio of oxygen to pentane of.! 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